Problem A (SW) What if the freezing point of a sugar solution that is 2m? kf = 1.86 (hint) get the change in freezing pt. using Atf = (kf)(m) then subtract from zero

Question

 

Problem A (SW)

What if the freezing point of a sugar solution that is 2m? kf = 1.86

(hint) get the change in freezing pt. using  Atf = (kf)(m) then subtract from zero

you should get a negative number in Celsius

 

Answer 1

You asked this previously, and it has been answered previously. If you are unhappy with the previous answer, or don't understand it, please make a comment and explain the problem. Tutors will be happy to respond to help you understand. Having said that, here is my solution once again.

I have no idea what Atf is supposed to mean in your equation, so here is the equation that I and others use.

Freezing point depression:

∆T = imK

∆T = change in freezing point = ?

i = van't Hoff factor = 1 for sugar (sucrose)

m = molality = moles sugar/kg water = 2 m

K = freezing point constant for water = -1.86

∆T = (1)(2)(1.86)

∆T = -3.72 degrees

New freezing point of solution = -3.7 degrees C