J.R. S. answered 03/26/20
Ph.D. University Professor with 10+ years Tutoring Experience
Freezing point depression:
∆T = imK
∆T = change in freezing point = ?
i = van't Hoff factor = 1 for sugar (sucrose)
m = molality = moles sugar/kg water = 2 m
K = freezing point constant for water = 1.86
∆T = (1)(2)(1,86)
∆T = 3.72 degrees
New freezing point of solution = -3.7 degrees C