Adam A. answered • 15d

Tutor for High School Level Math and Chemistry

Charles's Law is V1/T1 = V2/T2, where V1 and V2 are in liters and T1 and T2 are in Kelvin. Start by converting T1 = 20.0°C to Kelvin --> 20.0 + 273.2 = 293.2 K.

Then, divide V1 = 6.00 L by T1 = 293.2 K. This should come out to be 0.0205.

So again, we have V1/T1 = V2/T2 = 0.0205. Since V2 = 4.00 L, T2 = 4.00/0.0205, which is equal to 195.5 K.

To find the decrease in temperature, you just subtract 293.2 K - 195.5 K = 98 K = 98°C.