Chemistry Charles law problem

Question

Calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L

So i know the answer is 98°c but I'm really confused on how they got their answer.

If you could show me your work on how you get this answer i would really appreciate it, also if you wouldn't mind can you break the steps down for me so i can really understand it better. Thank you

Answer 1

Charles's Law is V1/T1 = V2/T2, where V1 and V2 are in liters and T1 and T2 are in Kelvin. Start by converting T1 = 20.0°C to Kelvin --> 20.0 + 273.2 = 293.2 K.

Then, divide V1 = 6.00 L by T1 = 293.2 K. This should come out to be 0.0205.

So again, we have V1/T1 = V2/T2 = 0.0205. Since V2 = 4.00 L, T2 = 4.00/0.0205, which is equal to 195.5 K.

To find the decrease in temperature, you just subtract 293.2 K - 195.5 K = 98 K = 98°C.