I can't solve this problem!

Question

At a certain temperature, the  for the decomposition of  is 

Initially, only  is present at a pressure of  in a closed container. What is the total pressure in the container at equilibrium?

Answer 1

H₂S(g) ===> H₂(g) + S(g)

0.165...............0.............0........Initial

-x....................+x...........+x.......Change

0.165-x...........x...............x.......Equilibrium

Kp = 0.850 = (H₂)(S)/(H₂S)

0.850 = (x)(x)/0.165-x

0.140 - 0.850x = x²

x² + 0.850x - 0.140 = 0

x = 0.141 atm

Final pressures are...

PH2S = 0.165 - 0.141 = 0.024 atm

PH2 = 0.141 atm

PS = 0.141 atm

TOTAL PRESSURE = 0.024 + 0.141 + 0.141 = 0.306 atm