Equations of parallel and perpendicular lines

Question

The equation for line S can be written as y-10= 5(x+3). parrell line to S is line T, which passes through the point ( 2,6 ). What is the equation for line T? it needs to be in slope intercept form ( y=mx+b)

Answer 1

Since the slope of line S is 5, the slope of the line parallel to is is also m=5. To find the equation of the line going through the point (2,6) use the following equation.

(y-y1)=m(x-x1) Plug in known values

(y-6)=5(x-2) Distribute

y-6=5x-10 Add 6 to both sides

y-6+6=5x-10+6 Simplify

y=5x-4