please show working

Question

2. The deep blue compound Cu(NH3)4SO4(s) is made by mixing solutions of copper sulfate and ammonia, and evaporating water away:

Cu2+(aq) + SO4 2- (aq) + 4NH3(aq) > Cu(NH3)4SO4(s)

(a) If you dissolve 25.0 g of CuSO4(s) in water, then add 25.0 g of NH3(aq), what is the theoretical yield of Cu(NH3)4SO4(s)?

(b) If the mass of Cu(NH3)4SO4(s) that you isolate is 15.5 g, what is the percentage yield of Cu(NH3)4SO4(s)?

Answer 1

I answered the first part in your previous question and the theoretical yield turned out to be

35.7 g Cu(NH₃)₄SO₄

The percent yield is the actual yield/theoretical yield x 100%

% yield = 15.5 g/35.7 g (x100%) =

Answer 2

Hi Mal F.,

What exactly is your difficulty here? Theoretical yields are based on combinations of moles of ingredients. So convert each input material into moles basis. Figure which materials (if any) are in excess, then calculate through for the limiting ingredient(s). Finally, convert back to a grams mass basis (that's usually what's done, anyway). So you'll need to figure molar masses for Cu++ ion, NH₃ , and SO₄ -- ion, and use them to do the conversions! (don't let the ionic charges throw you, electrons carry almost no mass, just do as atoms mass only)

-- Cheers, --Mr. d.