
Patrick B. answered 03/24/20
Math and computer tutor/teacher
x=6.5
y = 0.77 * 6.5^2 - 1.32 * 6.5 - 9.31
= 0.77 * 42.25 - 1.32 * 6.5 - 9.31
= 14.6425
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Minimizing the quadratic function y = 0.77x^2 - 1.32 x - 9.31
A=0.77 B=-1.32 C=-9.31
The max MAYBE occurs at:
-B/(2a) = 1.32/(0.77*2) = 1.32/1.54
= 132/154
= 66/77
= 6/7
the extrema is 0.77 (6/7)^2 - 1.32 (6/7) - 9.31 = -9 and 6/7 = -69/7 <--- disqualified
0 = 0.77x^2 - 1.32 x - 9.31
0 = 77x^2 - 132x - 931
132 +or- sqrt ( 132^2 + 4(77)(931)) / [2*77]
= [132 +or- sqrt( 304172)] / 154
negative branch also results in negative measures
the minimum occurs at:
(132 + sqrt(304172))/154 which is APPROXIMATELY 4.438