How many grams of MgCl2 will be produced from 16.0 g of Mg(OH)2 and 11.0 g of HCL?

Answer 1

Write the balanced equation:

Mg(OH)₂ + 2HCl ==> MgCl₂ + 2H₂O

moles Mg(OH)₂ present = 16.0 g Mg(OH)₂ x 1 mol/58.32 g = 0.274 moles

moles HCl present = 11.0 g HCl x 1 mol/36.5 g = 0.301 moles

Since it takes 2 moles HCl per 1 mol Mg(OH)₂, the HCl IS LIMITING

To find grams MgCl₂ formed, used the limiting reactant and stoichiometry...

0.301 mol HCl x 1 mol MgCl₂/2 mol HCl x 95.2 g/mol MgCl₂ = 14.3 g MgCl₂ formed