
Elijah H. answered 03/23/20
Hey! Call me Eli! I'm an undergraduate at KSU studying chemistry.
Hi Catherine! At your request, I will not be providing final solutions in this answer. Please contact me if you have more questions after reading.
For question a), you should use the relationship M1V1=M2V2. M in this case is molarity, and V is volume. If your initial solution is 0.1 M Fe(NO3)3, with a volume of 1.00 mL, and you dilute it to 6.00 mL, then you have the variables M1, V1, and V2. Use those to solve for M2. Be sure to use the same units on both sides! This equation works because the units of M are moles/liter. With this equation, you are certain that if you change either molarity or volume, the other must change as well.
For each solution in b), you should use the same relationship (M1V1=M2V2). The initial volume and final volume are the same for each solution. The changing variable is the molarity of the solution.
Question c) is worded somewhat oddly. You mentioned Beer's Law in your question, so I assume you have done or will do spectrophotometry on your samples. This would give you variables to plug into Beer's Law (A=c, where A is absorbance of incident light;
is the molar absorptivity coefficient of the species, which would be given;
is the path length, or how long the light travels--this would also be given; and c is the concentration of the species, which is the answer you want to solve for). Without that, I believe you could solve for the concentration of both Fe3+ and SCN- in the solution 1A using M1V1=M2V2 and take the lower number (as the limiting factor in formation of FeSCN2+ is the amount of the species present in lesser quantities).
I hope this helps!
Catherine S.
Thank You! This helped a lot!03/23/20