A sample of gas in a 1.40 L container at 475 kPa, at a temperature of 303K expands to fill a 3.50 L container. What is the new gas pressure if the temperature is now 268 K?

Answer 1

Combined Gas Law tells us

P1V1/T1 = P2V2/T2

P1 = 475 kPa

V1 = 1.40 L

T1 = 303K

P2 = ?

V2 = 3.50 L

T2 = 268K

(475)(1.40)/303 = (P2)(3.50)/268

Solve for P2:

P2 = 168 kPa