J.R. S. answered 03/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
Let us use the ideal gas law to find the number of moles of gas present.
PV = nRT
P = 1.10 atm
V = 1.75 L
R = 0.0821 Latm/Kmol
T = 63 + 273 = 336K
n = moles = PV/RT
n = (1.10 atm)(1.75 L)/(0.0821 Latm/Kmol)(336K)
n = 0.06978 moles
molar mass = 1.95 g/0.06978 moles = 27.9
density of gas = 1.95 g/1.75 L = 1.11 g/L