How many grams of ZnCl2 will be produced from 22.0g of Zn and 14.0g of HCl

Answer 1

If given the mass of both reactants, one must determine which reactant, if any, is in limited supply. We can do this as follows:

Zn + 2HCl ==> ZnCl₂ + H₂ ... balanced equation

For Zn: 22.0 g Zn x 1 mol Zn/65.4 g x 1 mol ZnCl₂/mol Zn x 136 g ZnCl₂/mol = 45.8 g ZnCl₂ formed

For HCl: 14.0 g HCl x 1 mol HCl/36.5 g x 1 mol ZnCl₂/2 mol HCl x 136 g ZnCl₂/mol = 26.1 g ZnCl₂ formed

From the above calculations you can see that the maximum amount of ZnCl₂ that can be formed under these conditions is 26.1 g because HCl is limiting.