J.R. S. answered 03/19/20
Ph.D. University Professor with 10+ years Tutoring Experience
It's easier if you first write the complete molecular equation.
AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq) ... you can refer to your solubility rules for the phases
Since AgCl(s) is a precipitate, only the Ag+ and Cl- will appear in the net ionic equation.
Net ionic: Ag+(aq) + Cl-(aq) ==> AgCl(s)
If you want to see how this is obtained from the total ionic equation, see below:
Total ionic: Ag+(aq) + NO3-(aq) + K+(aq) + Cl-(aq) ==> AgCl(s) + K+(aq) + Cl-(aq)
K+(aq) and NO3-(aq) are spectator ions and cancel leaving you with the net ionic as shown above.