What mass of water will change its temperature by 3 0C when 525 J of heat is added to it? The specific heat of water is 4.18 J/g C

Question

Measuring Heat Q=mc∆T

Answer 1

As in the previous question you asked, you can use q = mC∆T

q = 525 J

m = ?

C = 4.18 J/g/deg

∆T = 30º (I think it's 30, or maybe it is 3 degrees. I'm going with 30 degrees)

525 J = (m)(4.18 J/g/deg)(30 deg)

525 J = 125.4 J/g (m)

m = 525 J/125.4 J/g

m = 4.19 g