How many joules of heat are lost by 358, 000 g granite as it cools from 41.2C to -12.9C and has a specific heat of 1.023 J/gC ?

Question

Measuring Heat Q=mc∆T

Answer 1

For this type of problem, you can use the formula q = mC∆T

q = heat = ?

m = mass = 358,000 g

C = specific heat = 1.023 J/g/deg

∆T = change in temperature = -12.9º - 41.2º = 54.1ºC

q = (358,000 g)(1.023 J/g/deg)(54.1 deg) = 19,813,259 J = 19,800,000 J (to 3 significant figures)