Given N2 + O2 →2NO ∆H=180.7 determine the enthalpy of the reverse reaction? Is the reverse reaction endothermic or exothermic

Question

Thermochemical equation

Answer 1

N₂ + O₂ ==> 2NO ∆H = 180.7 units aren't given but assumed to be kJ

reverse reaction is...

2NO ==> N₂ + O₂ and the ∆H = -180.7 kJ. Since the sign is negative, this is exothermic.