J.R. S. answered 03/18/20
Ph.D. University Professor with 10+ years Tutoring Experience
Again, since they are giving you the mass of BOTH reactants, you must find which reactant, if any, is limiting.
73.0 g NH3 x 1 mol NH3/17 g x 6 mol H2O/4 mol NH3 x 18 g H2O/mol = 116 g H2O formed
73.0 g O2 x 1 mol O2/32 g x 6 mol H2O/5 mol O2 x 18 g H2O/mol = 49.3 g H2O formed is maximum mass
Since only 49.3 g of H2O can be formed, this makes the O2 the limiting reactant and NH3 is present in excess.