Here are the steps to solve this question:
1. Convert 7.65g of phosphorus to moles by dividing by the molar mass of phosphorus:
(7.65g P) x (1 mole P / 30.97g P) = 0.24701 mole P
2. Use the ratio of stoichiometric coefficients to convert moles of phosphorus to moles of diphosphorus pentoxide:
0.24701 mole P x (2 mole P2O5 / 4 mole P) = 0.123505 mole P2O5
3. Convert the moles of diphosphours pentoxide to grams by multiplying by the molar mass of P2O5:
0.123505 mole P2O5 x (141.94g P2O5 / 1 mole P2O5) = 17.5g P2O5
Here is the work all in one line:
(7.65g P) x (1 mole P / 30.97g P) x (2 mole P2O5 / 4 mole P) x (141.94g P2O5 / 1 mole P2O5)
=17.5g P2O5