
Jack L. answered 03/14/20
Princeton PhD Student, Yale Graduate, and Experienced Tutor
Yes! For a matrix to be symmetric, it must equal its own transpose. Now let us consider (AAT)T (the transpose of your matrix). We know that in general for the product of two matrices AB, (AB)T = BTAT. Furthermore, we know that the tranpose of a transpose is the original matrix. Combining these two facts, we can deduce that
(1) (AAT)T = (AT)TAT = AAT
Thus, we found that the transpose of AAT equals itself; thus, it must be symmetric. We could then follow the exact same process with ATA to get the same result. I hope that helps!