If you start with 2 grams of aluminum metal, how many moles of H2 gas would you expect to produce?

Question

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Answer 1

Let us assume that the aluminum is reacting with HCl.

2Al(s) + 6HCl ==> 2AlCl₃(aq) + 3H₂(g) ... balanced equation

moles Al used = 2 g x 1 mol/27 g = 0.074 moles

moles H₂ produced = 0.074 moles Al x 3 moles H₂/2 moles Al = 0.111 moles H₂ gas = 0.1 moles H₂ gas