J.R. S. answered 03/13/20
Ph.D. University Professor with 10+ years Tutoring Experience
The buffering capacity will be completely lost as soon as there is no more conjugate base (C6H5COO-). The actual calculation of "buffer capacity" is different from what is being asked here (see below). So, to answer the question as it is asked, we will have to determine the volume of 0.410 M HCl needed to react completely with the conjugate base.
moles conjugate base = 175 ml x 1 L/1000 ml x 0.480 mole/L = 0.084 moles C6H5COO-
Reaction taking place is C6H5COO- + HCl ==> C6H5COOH + Cl-
moles HCl needed = 0.084 moles C6H5COO- x 1 mol HCl/mol C6H5COO- = 0.084 moles HCl needed
Volume of HCl needed: (x L)(0.410 mol/L) = 0.084 moles
x = 0.2049 L = 204.9 mls = 205 mls of HCl
NOTE: Buffer capacity is generally defined as the moles of an acid or base necessary to change the pH of a solution by 1 when added to 1 liter of buffer.