What is the empirical formula of a compound composed of 34.3 g of potassium ( K ) and 7.02 g of oxygen ( O )?

Question

What is the empirical formula of a compound composed of  of potassium () and  of oxygen ()? 

Answer 1

Please refer to the previous answer to a similar question about empirical formula.

moles K = 34.3 g x 1 mol/39.1 g = 0.877 moles K

moles O = 7.02 g x 1 mol/16 g = 0.439

Dividing both by 0.439 we obtain

0.877/0.439 = 1.99 = 2 moles K

0.439/0.439 = 1.00 = 1 mole O

Empirical formula = K₂O