Chemistry problem for HW

Question

How many milliliters of an aqueous solution of 0.189 M chromium(II) acetate is needed to obtain 18.3 grams of the salt?

Answer 1

The molar mass of chromium(II) acetate, Cr(CH3CO2)2, is 170.08 g/mol (for the monomer)

18.3 g x 1 mol/170.08 g = 0.108 moles wanted

(0.189 mol/L (x L) = 0.108 moles

x = 0.571 L = 571 mls

Check:

0.571 L x 0.189 mol/L x 170 g/mol = 18.3 g