How many grams of AG will be produced from 5.00 g of CU in 1.00 g of AgNO3

Answer 1

Cu(s) + 2AgNO₃(aq) ==> Cu(NO₃)₂(aq) + 2Ag(s)

5.00 g Cu x 1 mol Cu/63.5 g x 2 mol Ag/mol Cu x 108 g Ag/mol = 17.0 g Ag formed