A sample of an ideal gas has a volume of 2.39 L at 288 K and 1.13 atm. Calculate the pressure when the volume is 1.32 L and the temperature is 303 K.

Answer 1

P₂V₂ /T₂= P₁V₁/T₁ 

Rearrange to get pressure, P₂

P₂= T₂P₁V₁/ V₂T₁

P₂= (303K x 1.13 x 2.39) /(1.32 x 288K)

P₂= 2.15 atm

Answer 2

V1 = 2.39 L

T1 = 288K

P1 = 1.13 atm

V2 = 1.32 L

T2 = 303K

P2 = ?

Use the combined gas law: P1V1/T1 = P2V2/T2 and solve for P2...

P2 = P1V1T2/V2T1

plug in the above values and solve