solve [ 0, 2pie ]

Question

How do you solve [ 0, 2pie ] when tan^-1(2.37)

Answer 1

I think the problem should be: "Solve tan^-1(2.37) on [0,2π]" (π is "pi" not "pie")

tan^-1(2.37) ≈ 67.123^o

This angle is in Q1 (quadrant 1). However, if you think about all 4 quadrants, Q3 also has angles with a positive tangent (recall tan(θ) = y/x so if both y and x are negative values, the tangent is positive):

tan^-1(2.37) ≈ 67.123^o + 180^o = 247.123^o

To sanity-check your answers, you can go to a graphing site like desmos and graph tan(θ) for θ = 0...2π. When I do that, I see these are the only solutions on [0, 2π].