J.R. S. answered 03/09/20
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From the Henderson Hasselbalch equation...
pOH = pKb + log [salt]/[base]
pOH = 5.77 + log (0.513/0.183)
pOH = 5.77 + 0.45
pOH = 6.22

J.R. S.
03/16/20