Calorimetry part 4

Question

A 52.19 mL sample of 3.02 M CuSO4 reacts with 54.48 mL of 2.87 M KOH in a coffee cup calorimeter to form Cu(OH)2(s) and K2SO4 (aq). The initial temperature is 18.5°C and the final temperature is 44.9°C. Assume that the mixture has the same specific heat as water and the same density as water. Specific heat of water is 4.184 J/g-K.

d.) Which reactant is the limiting reagent?

Answer 1

See previous answers...

CuSO₄(aq) + 2KOH(aq) ==> Cu(OH)₂(s) + K₂SO₄(aq)

b). moles CuSO4 = 52.19 ml x 1L/1000 ml x 3.02 mol/L = 0.158

moles KOH = 0.156 moles

Limiting reactant = KOH since mol ratio is 2 KOH : 1 CuSO4