Patrick B. answered 03/07/20
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Math and computer tutor/teacher
Prob. Of 7 or more (6+5+4+3+2+1)/36= 21/36=7/12
Prob 5,6,10,12 = (4+5+3+1)/36=13/36
Sofia M.
asked 03/07/20Event A: The sum is greater than 6
Event B: The sum is divisible by 5 or 6
Patrick B. answered 03/07/20
Math and computer tutor/teacher
Prob. Of 7 or more (6+5+4+3+2+1)/36= 21/36=7/12
Prob 5,6,10,12 = (4+5+3+1)/36=13/36
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