Acid and Bases Titration Lab

Question

using Stoichiometry and the balanced equation, find the moles of acetic acid used in each of your vinegar titrations.

Balanced Equation: NaOH + CH₃COOH—>NaCH₃COO +H₂O

Titration 1: 5.361x10^-3Moles NaOH & 5.60mL Acetic Acid

Titration 2: 4.441x10^-3Moles NaOH & 5.30mL Acetic Acid

Titration 3: 4.380x10^-3Moles NaOH & 5.12mL Acitic Acid

Answer 1

From the balanced equation you can see that ONE mole acetic acid reacts with ONE mole NaOH, i.e tge mole ratio is 1:1.

The moles of acetic acid is the same as the moles NaOH which is already given. Perhaps you mean to ask “what is the concentration “? In that case it is moles/liters so for titration #1 you have

5.361x10^-3 0.00560 L = 0.9573 M