How many grams of aluminum chloride can you make if 3.70L of Chlorine gas at STP reacts with excess aluminum? Hint: Do the Balanced equation first; be careful with formulas

Question

2Al+3Cl2–>2AlCl3 is the balanced equation but I’m unsure of where to go from here

Answer 1

2Al + 3Cl₂ ==> 2AlCl₃. ... balanced equation

Find moles of Cl₂^::

3.70 L x 1 mol/22.4 L = 0.165 moles Cl₂

Next find moles and grams of AlCl₃:

0.165 mol Cl₂ x 2 mol AlCl₃/3 mol Cl₂ = 0.110 mol AlCl₃

mass = 0.110 mol AlCl₃ x 133 g/mol = 14.6 g AlCl₃