J.R. S. answered 03/03/20
Ph.D. University Professor with 10+ years Tutoring Experience
2C2H6 + 7O2 ==> 4CO2 + 6H2O ... balanced equation
The heat of combustion for this reaction will be equal to the sum of the enthalpy of formation of the products - the sum of the enthalpy of formation of the reactants. Or...
∆Hrxn = ∑∆Hproducts - ∑∆Hreactants
Look up ∆Hformation CO2 and multiply it by 4 and add that to 6x the ∆H for H2O
From that value subtract 2x the ∆Hformation for ethane and that will give you the answer
NOTE: the ∆Hformation for O2 is zero so doesn't need to be included in the equation