In the gas mixture containing 88 grams of oxygen gas (O2), 88 grams of nitrogen gas (N2), and 12 grams of nitrogen dioxide gas (NO2), what is the mole fraction of nitrogen gas?

Question

0.45

0.51

0.81

0.12

Answer 1

88 g O₂ x 1 mol O₂/32 g = 2.75 moles O₂

88 g N₂ x 1 mol N₂/28 g = 3.14moles N₂

12 g NO₂ x 1 mol NO₂/46 g = 0.261 moles NO₂

TOTAL moles = 6.15 moles

mole fraction N₂ = 3.14/6.15 = 0.511