If 10 g of Ni reacts with 4 g of S, how many grams of NiS is produced?

Answer 1

First, write a correctly balanced equation:

Ni + S ==> NiS

Next, find which reactant is in limiting supply:

moles Ni = 10 g Ni x 1 mol Ni/59 g = 0.17 moles Ni

moles S = 4 g S x 1 mol S/32 g = 0.031 moles S

Since the balanced equation shows a 1:1 mole ratio of Ni and S, the S is in limiting supply

Finally, find grams of NiS produced:

0.031 moles S x 1 mol NiS/mol S x 91 g NiS/mol NiS = 2.8 g = 3 g NiS produced (to only 1 sig. fig.)

Answer 2

Hi Julie S.,

See comment on your latest question in your problem set series. Not necessary to post them all onto Wyzant; look at the approach and apply it to all your similar problems. To reiterate: 1) convert given masses to moles of each reactant. 2) write balanced equation for reaction 3) compare given reactants' moles ratio to reaction mole ratio (for reactants), find which reactant is limiting (or, is it balanced as is?) 4) carry the limiting moles reactant through to product using reaction stoichiometry 5) convert product(s) back to mass basis 6) examine results for errors!

-- Cheers, -- Mr. d.