Suppose you want to draw a rectangle where the width is 3 3 inches more than the length and the diagonal is 6 6 inches longer than the length. What are the dimensions of the rectangle?

Answer 1

W = 33 + L

D = 66 + L

The diagonal D squared = sum of squares of L and W

D² = L² + W² You have 3 equations, 3 unknowns, which should lead to a unique solution

(66+L)² = L² + (33+L)²

4356 + 132L + L² = L² + 1089 + 66L + L²

L² -66L - 3267 = 0

L² - 66L + 1089 -3267 - 1089 = 0

(L-33)² = 4356

L = 33 + or - sqr4356 = 33 +66 = 99

W = L+33 = 99 +33 = 132

L=99 inches, W = 132 inches D= 165 inches