A gas mixture contains 88 grams of oxygen gas (O2), 88 grams of nitrogen gas (N2), and 12 grams of nitrogen dioxide gas (NO2) What is the mole fraction of nitrogen dioxide in this mixture?

Question

0.45

0.51

0.04

0.12

Answer 1

88 g O2 x 1 mol/32 g = 2.75 mole

88 g N2 x 1 mol/28 g = 3.14 mole

12 g NO2 x 1 mol/46 g = 0.261 mole

TOTAL MOLES. = 6.15

mole fraction NO2 = 0.26/6.15 =. 0.04