NaOH (aq) + HCI (aq) -> H2O + NaCI (aq) If 25.0 mL of a 0.2 M NaOH solution is used for the reaction shown above, how many moles of NaOH were involved in the reaction? ____ moles

Answer 1

NaOH(aq) + HCl(aq) ==H2O(l) + NaCl(aq) ... balanced equation

moles HCl used = 25.0 ml x 1 L/1000 ml x 0.2 mol/L = 0.005 moles HCl

According to the balance equation, 1 mol NaOH reacts with 1 mol HCl so the moles of NaOH involved in the reaction would be 0.005 moles.

Answer 2

The same as the number of moles of HCl.