Aluminum Chemistry Question

Question

A piece of aluminum has a mass of 8.550 g, a length of 4.15 cm, and a width of 6.25 cm. Calculate the thickness in mm where the density of aluminum is 2.70 g/cm³. (volume of rectangle L x W x H)

Answer 1

To find the thickness (height) we can use L x W x H = volume, but first we need to find the volume.

We can find the volume by using the mass and the density, since density is given in units of mass/volume (2.70 g/cm³).

8.550 g x 1cm³/2.70 g = 3.17 cm³ = volume

volume = L X W X H

3.17 cm3 = (4.15 cm)(6.25 cm)(H cm)

H = 3.17/25.9

H = 0.122 cm

Converting to mm:

0.122 cm x 10 mm/cm = 1.22 mm