In what amount of water (mol) there are as many hydrogen atoms as there are in 5,6 l of ammonia

Answer 1

Assuming standard temperature and pressure (STP):

5.6 L NH₃ x 1 mol/22.4 L = 0.25 moles NH₃

0.25 mol NH₃ x 6.02x10²³ molecules/mole x 3 H atoms/molecule NH₃ = 4.5x10²³ H atoms

4.5x10²³ H atoms x 1 molecule H₂O/2 H atoms x 1 mol H₂O/6.02x10²³ molecules = 0.37 moles H₂O

Answer 2

Hello Mateusz!

The density of ammonia, at STP is 0.769 kg/m³,converting the proper units is 0.769 g/l

Knowing the molecular weight of ammonia to be 18 g/mol. We have:

5.6 l* 0.769 g/l * (1 mol/17 g) = 0.253 mol of ammonia

Ammonia has the molecular formula of NH₃, so there is 3 times the number of Hydrogen atoms than ammonia molecules, so there is:

3*0.253 = 0.760 mols of H atoms

Water has the formula H₂O, so 2 hydrogen atoms per molecule of water, so the answer to the question will be:

1/2 * 0.760 = 0.380 mol of water