The diagram of circle V, where two chords JK------ and LM-----, are equidastant from the center

Question

If JK= 3x+19 and LM= 6x+7, what is the length of the segmente JK?

a) 15.5

b) 31

c) 24

d) 3

Answer 1

If 2 chords are equidistant from the center, they must have the same length.

3x+19=6x+7 --> x4 and JK = 31.

Answer 2

Chords equidistant from the center of a circle are congruent. Therefore, you can write

JK = LM

Substitute the given expressions for JK and LM

3x + 19 = 6x + 7

Solve for x

x = 4

Substitute back into given expression to get JK = 31.