What is the equation of the line, in slope-intercept form, that is perpendicular to the line with the equation y=6x−1 and passes through the point (−6,4)?

Question

y=6x+22

y=−1/6x−16/3

y=6x+40

y=−1/6x+3

Answer 1

the slope of the perpendicular line is the negative inverse of the slope of the given line: negative inverse of 6 is -1/6

IF it goes through the point (-6,4) then plug those numbers into the

slope intercept form of y=mx+b with x=-6 and y=4, solve for b

4=(-1/6)((-6) + b solve for b

4=1+b

b=4-1=3

y=(-1/6)x+3