J.R. S. answered 02/19/20
Ph.D. University Professor with 10+ years Tutoring Experience
NH2COONH4(s) <===> 2NH3(g) + CO2(g)
Since ammonium carbamate is a solid, it does not appear in the equilibrium expression. Thus, we have...
Kc = 0.568 = [NH3]2[CO2] = (2x)2(x) = 4x3
x3 = 0.142
x = 0.522
At equilibrium...
[NH3] = 2x = 2*0.522 = 1.04
[CO2] = x = 0.522
PV = nRT
P = nRT/V and n/V = concentration
P = concentration x RT
Ptotal = (1.04)(0.0821)(340) + (0.522)(0.0821)(340) = 29.14 + 14.57 = 43.71 atm (differs from answer given because of rounding)