Judite S.

asked • 02/17/20

What is the equation of the line that is parallel to y−5=−1/3(x+2) and passes through the point (6,−1)? The equation will be in slope-intercept form.


y=−x/3−17/3

y=x/3+19/3

y=x/3+1

y=−x/3+1

y=−x/3−1

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