Find the​ center-radius form for the circle having the endpoints (3,8) and (-7,2) of a diameter.

Answer 1

Hi Amber,

(3,8) and (-7,2) are start and end of diameter

so the mid point is center of circle

center = ( 3-7/2 , 8+2/2) = (-2 , 5)

radius = the distance between center and one of given point

radius = √(-2-3)² + (5-8)²

radius = √25 +9= √34

Equation of circle is (x+2)² + (y-5)² = (√34)² =34

I hope it is useful,

Minoo