J.R. S. answered 02/17/20
Ph.D. University Professor with 10+ years Tutoring Experience
F2(g) + Br2(g) <==> 2BrF(g)
1.99......2.88.................0........Initial
-x.......-x....................+2x........Change
1.99-x....2.88-x........1.117......Equilibrium
2x = 1.117
x = 0.5585 atm
At equilibrium....
F2 = 1.99 - 0.559 = 1.431atm
Br2 = 2.88 - 0.559 = 2.321 atm
BrF = 1.117 atm
Kp = P(BrF)2 / P(F2)P(Br2) = (1.117)2 / (1.431)(2.321)
Kp = 0.376