J.R. S. answered 02/14/20
Ph.D. University Professor with 10+ years Tutoring Experience
4NH3(g) + 5O2(g) ==> 4NO(g) + 6H2O(g) ... balanced equation
mol O2 consumed = 0.162 mol NH3 x 5 mol O2/4 mol NH3 = 0.203 mol O2 consumed
mol NO produced = 0.162 mol NH3 x 4 mol NO/4 mol NH3 = 0.162 mol NO produced
mol H2O produced = 0.162 mol NH3 x 6 mol H2O/4 mol NH3 = 0.243 mol H2O produced