A student increases the temperature of a 200 cm balloon from 60°C to 180°C. What will the new volume of the balloon be? (Be careful with units.)

Question

272 cm^3

236 cm^3

100 cm^3

600 cm^3

Answer 1

Assuming constant pressure (expansion of the balloon), we can use Charles Law.

V1/T1 = V2/T2

V1 = 200 cm³

T1 = 60+273 = 333K

V2 = ?

T2 = 180+273 = 453K

Solving for V2, we have...

V2 = V1T2/T1

V2 = (200)(453)/333

V2 = 272 cm³