I need help on a trig word problem

Question

The angle of elevation from the far side of a pool to the top of a waterfall is 65 degrees and the distance from the far side of the pool to the top of the waterfall is 160 feet.

a. Find the height of the waterfall to the nearest tenth of a foot.

b. Find the width of the pool to the nearest tenth of a foot.

 

(I only need part b)

Answer 1

cos=adjacent/hypotenuse

cos(65)=x/160

0.4226182=x/160

160*0.4226182=x

x=67.6189

x=67.6 feet

Did you get 145.0 feet for the height of the waterfall ?

 

sin(65)=x/160

0.9063=x/160

x=160*0.9063

x=145.0 feet

the vertical height can't be greater than the diagonal distance

160²=67.6²+145²

25,600=4569.76+21,025

25,600≈25,594.76

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