Arthur D. answered 02/12/20
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
RA*TA=360
RB*TB=60
RA=3RB
TA+TB=12
3RB*(12-TB)=360
3RB(12-60/RB)=360
36RB-180=360
36RB=540
RB=15
so RA=45
45TA=360
TA=8
so TB=4
45-15+8-4=34
Arthur D. answered 02/12/20
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
RA*TA=360
RB*TB=60
RA=3RB
TA+TB=12
3RB*(12-TB)=360
3RB(12-60/RB)=360
36RB-180=360
36RB=540
RB=15
so RA=45
45TA=360
TA=8
so TB=4
45-15+8-4=34
Mark H. answered 02/12/20
Tutoring in Math and Science at all levels
You have 4 unknowns, and you are given 4 equations. Since there are 4 unique equations, there is enough information to solve the problem
RATA = 360
RBTB = 60
RA = 3RB
TA+TB = 12
The 3rd equation relates RA and RB. We can start by finding another equation with the same variables. The 1st 2 equations allow us to relate the "T" variables to the "R" variables:
TA = 360/RA
TB = 60/RB
Next, substitute into equation 4 to get:
360/RA + 60/RB = 12
Now, we have 2 equations with RA and RB. Solve using substitution to get RA and RB.
Once you have RA and RB, use the the first 2 equations to get TA and TB.
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