How do I calculate liters of CO2 at stp

Question

How do I calculate liters of CO2 at stp from 1,995,852 g of octane

Answer 1

Octane = C₈H₁₈

Combustion of octane is 2C₈H₁₈ + 25O₂ ==> 16CO₂ + 18H₂O

Convert the g of octane to moles. Grams/molar mass = moles

1,995,852 g x 1 mol/114 g = 17,507 moles octane

17,507 moles octane x 16 mol CO₂/2 mol octane=140,060 mol CO₂

At STP 1 mol ideal gas = 22.4 L

140,060 mol CO₂ x 22.4 L/mol = 3,147,339 liters